iphone - How to compare a NSNumber in an if -

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how to:

if (mynsnumber == 1) {  ... }

this doesn't seem build

the object:

if mynsnumber nsnumber, code should read,

if ([mynsnumber intvalue] == 1) {     ... }

if nsinteger, can directly compare integer literal. because nsinteger primitive data type. 

if (mynsnumber == 1) {     ... }

note: make sure don't have * in declaration. nsinteger declarations should read,

nsinteger mynsnumber; // right nsinteger *mynsnumber; // wrong, nsinteger not struct, primitive data type.

the following based on @boltclock's answer, posted here

however if need use pointer nsinteger (that is, nsinteger *) reason, need dereference pointer value:

if (*mynsnumber == 11) { }

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