Methods call in random order (C#) -

i want write c# program executes several methods a(), b() , c() in random order. how can that?

assuming random number generator declared this:

public static random rnd = new random(); 

let’s define shuffle function bring list random order:

/// <summary> /// brings elements of given list random order /// </summary> /// <typeparam name="t">type of elements in list.</typeparam> /// <param name="list">list shuffle.</param> /// <returns>the list operated on.</returns> public static ilist<t> shuffle<t>(this ilist<t> list) {     if (list == null)         throw new argumentnullexception("list");     (int j = list.count; j >= 1; j--)     {         int item = rnd.next(0, j);         if (item < j - 1)         {             var t = list[item];             list[item] = list[j - 1];             list[j - 1] = t;         }     }     return list; } 

^{_{this shuffle implementation courtesy of romkyns!}}

now put methods in list, shuffle, run them:

var list = new list<action> { a, b, c }; list.shuffle(); list.foreach(method => method());