byte - Java stripping zeros from function -

i'm trying flip bytes around in java , function have working correctly bytes , failing others.

the function using this:

public static int foldinbyte(int m, int pos, byte b) {     int tempint = (b << (pos * 8));     tempint = tempint & (0x000000ff << (pos * 8));     m = m | tempint;     return m; } 

and code implements is:

byte[] bitmaskarray = new byte[]{                             bytebuffer.get(inputindex),                             bytebuffer.get(inputindex + 1),                             bytebuffer.get(inputindex + 2),                             bytebuffer.get(inputindex + 3)};                         int tempint = 0;                          tempint = foldinbyte(0, 3, bitmaskarray[3]);                         tempint = foldinbyte(tempint, 2, bitmaskarray[2]);                         tempint = foldinbyte(tempint, 1, bitmaskarray[1]);                         tempint = foldinbyte(tempint, 0, bitmaskarray[0]);                          bitmask = tempint; 

the bytes being read bytebuffer byteorder being little endian.

for example, bytes 00 01 b6 02 set bitmask to: 2b60100 - works in program.

however, if bytes a0 01 30 00, bitmask set to: 3001a0 - has stipped last 0 bitmask.

is there way can stop java stipping off trailing zeros?

i hope makes sense.

thanks

tony

the zeros not being stripped -- both examples cited correct.

• 00 01 b6 02 4-byte little-endian 2b60100
• a0 01 30 00 4-byte little-endian 3001a0

the zeros there, not being printed. system.out.print family of calls not print leading 0 digits.

i might mention method needlessly complex. here single method computes same value:

static int extractlittleendian4(byte[] buf, int index) {     int = buf[index+0]&0xff, b = buf[index+1]&0xff, c = buf[index+2]&0xff, d = buf[index+3]&0xff;     return | (b << 8) | (c << 16) | (d << 24); }