java - Scanner without delimiter -

i able parse strings following: "123456abcd9876az45678". bnf this:

number: ? definition of int ? word: letter { , letter } expression: number { , word , number } 

however class java.util.scanner doesn't allow me following:

scanner s = new scanner("-123456abcd9876az45678"); system.out.println(s.nextint()); while (s.hasnext("[a-z]+")) {     system.out.println(s.next("[a-z]+"));     system.out.println(s.nextint()); } 

ideally, should yield:

-123456 abcd 987 az 45678 

i hoping java.util.scanner me, looks have create own scanner. there present in java api me?

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the question miss information. , therefore answers valid question not problem.

unfortunately cannot use no delimiters scanner class afaik. if wish ignore delimiters, you'd need use methods such findinline() or findwithinhorizon(). in case, findwithinhorizion() appropriate.

scanner s = new scanner("-123456abcd9876az45678"); pattern num = pattern.compile("[+-]?\\d+"); pattern letters = pattern.compile("[a-za-z]+"); system.out.println(s.findwithinhorizon(num, 0)); string str; while ((str = s.findwithinhorizon(letters, 0)) != null) {     system.out.println(str);     system.out.println(s.findwithinhorizon(num, 0)); }