javascript - Filter n arrays by excluding values that don't exist in each -

i have n arrays need determine if x in of n arrays. (where n number, , x numeric value) have following in place, it's ending false.

function filterarrays() {   var x = $(this).attr('id'); // ex: 2   var arrays = [[1,2,3],[2,4,6]];   var result = false;   each (var n in arrays)   {     result = result ^ (n.indexof(x) > -1);   } } 

how make result equal true when x in both arrays, when x not in both arrays, make result equal false?

the function above used jquery's filter() method. example:

$(arrayofelementswithnumericids).filter(arrayfilter); // arrayofelementswithnumericids prototype: [div#1,div#2,div#3,...] 

i'm thinking bitwise operation called for, wrong. please explain why solution right , why mine isn't working. (for bonus points)

here issues example:

• comparing number string (id string). use x = parseint(...)
• using ^ operator. instead initialize result true , use &&.
• get rid of each. correct syntax for (key in object)

i've modified code little possible:

function filterarrays() {     var x = parseint($(this).attr('id')); // ex: 2     var arrays = [[1,2,3],[2,4,6]];     var result = true;     (var n in arrays)     {         result = result && (arrays[n].indexof(x) > -1);     }     return result; } 

that being said, can optimize code using array.every() , array.some(). also, using $(this).attr('id') creates jquery object unnecessarily since can this.id directly.

function filterarrays() {     var x = parseint(this.id); // ex: 2     var arrays = [[1,2,3],[2,4,6]];     var result = arrays.every(function(array)     {         return array.some(function(item)         {             return item === x;         });     });     return result; }