Date parse in javascript -

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i need parse date in javascript 17dec2010 javascript date. how that?

the short answer is: there's no standard means in javascript doing that, you'll have yourself. javascript got any standard string representation dates (as of ecmascript 5th edition, year ago — format simplified version of iso-8601), , format doesn't match format.

however, there add-on libraries can help, such datejs.

your particular format pretty easy parse (see below), if variations, can complex fast.

simple example:

var months = {     en: {         "jan": 0,         "feb": 1,         "mar": 2,         "apr": 3,         "may": 4,         "jun": 5,         "jul": 6,         "aug": 7,         "sep": 8,         "oct": 9,         "nov": 10,         "dec": 11     } }; var datestring = "17dec2010"; var dt = new date(     parseint(datestring.substring(5), 10),               // year     months.en[datestring.substring(2, 5).tolowercase()], // month     parseint(datestring.substring(0, 2), 10)             // day ); alert(dt); // alerts "fri dec 17 2010 00:00:00 gmt+0000 (gmt)" or similar

live example

...but handles english (hence en property of months) , again, can complex quickly.

mplungjan quite correctly points out above fail on, "7dec2010". here's version that's bit more flexible, again, i'd library if there's variety in format:

var months = {     en: {         "jan": 0,         "feb": 1,         "mar": 2,         "apr": 3,         "may": 4,         "jun": 5,         "jul": 6,         "aug": 7,         "sep": 8,         "oct": 9,         "nov": 10,         "dec": 11     } }; var datestring = "17dec2010"; var parts = /^(\d+)(\d+)(\d+)$/.exec(datestring); if (parts && parts.length == 4) {   var dt = new date(       parseint(parts[3], 10),            // year       months.en[parts[2].tolowercase()], // month       parseint(parts[1], 10)             // day   );   display(dt); } else {   display("date '" + datestring + "' not recognized"); }

live example


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