java - How to use the equivalent of indexof() with biginteger in VB.Net? -

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i trying sum digits in large number. have gotten length of number with
l = answer.bitlength() can't figure out how increament through each digit using loop. ideas?

i'm using java.math.biginteger.

visual studio 2005 version 2.0

i should add can't seem use <> or of simple math options biginteger i'm using. if tell me how use different biginteger more willing swap.

dim answer java.math.biginteger dim sum integer = 0 dim x integer dim integer 'sets value of answer equal 1 answer = java.math.biginteger.valueof(1)  'gets 100! = 1 100 answer = answer.multiply(java.math.biginteger.valueof(i)) next  'gets length of answer dim l integer l = answer.bitlength()  'sums digits in 100! x = 0 l - 1 'need pull each character here add them next

final solution summing digits. wageoghe.

dim r integer dim s integer s = 0 while (answer.compareto(java.math.biginteger.valueof(0)) > 0)  r = answer.mod(java.math.biginteger.valueof(10)).tostring() s = s + r answer = answer.divide(java.math.biginteger.valueof(10))  end while

something should work:

    dim bi new system.numerics.biginteger(12345)     dim c char     dim s long      s = 0      each c in bi.tostring()         s = s + integer.parse(c.tostring())     next

or more conventional way using mod , / (integer division)

    dim bi new system.numerics.biginteger(12345)     dim s long     dim r integer      s = 0      while bi <> 0         r = bi mod 10         s = s + r         bi = bi / 10     end while

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