legacy - When is it time to port an old application to new platform? -

-

i'm working company has established application written in vb6. application stable , continues provide company income. however, beginning show age , noises been made port more modern platform such .net.

since hardly ever cut , dry decision appreciate input on when time port long standing application modern platform.

some of pros , cons have worked through:

in favor of porting

  • finding skills old programming language becomes harder , more expensive
  • support platform vendor ends @ point
  • leveraging modern programming practises on old platform becomes harder or impossible
  • rewriting provides opportunity improve existing practises
  • moving modern platform motivating development team
  • moving modern platform provides marketing opportunities

against porting

  • "if not broken don't fix it"
  • the cost of rewriting versus return
  • risks associated transition old new application
  • upskilling existing software engineers

some related stackoverflow questions:

one of things consider porting application can more , more expensive on time. have seen applications writen in 'ancient' languages developed. but, happens many times, domain knowledge in code , in heads of developers, not in up-to-date documents.

so in situations porting means not rewriting in new sparkly language reverse-enginering specs , picking the, available, brains of developers. becomes harder , harder on time.

an other thing 'porting' hardly ever easy migration wizard want believe. many wizards produce half-baked solution still constructed according constructs , features common 'legacy' environment , hardly using new features , possibilities. might not seem bad if leave @ level in fact making hard developers know 'new' language understand code , make porting next platform or language harder. call legacy in capitals. dragging useless stuff around decades.

the optimal moment start porting, developer's point of view, yesterday.

the optimal moment start porting, manager's point of view, tomorrow.

the optimal moment start porting, competitor's point of view, never.


Comments

Post a Comment

Popular posts from this blog

java - SNMP4J General Variable Binding Error -

-
i trying use snmp4j snmp bulkget. when ever use snmp4j make call returned responseevent error says "general variable binding error" , data returned equal null. to debug: print out, console, exact oid , version number using in snmp4j. use printed out data snmpwalk on command line. valid results. know sending snmp4j correct pdu correct oid, version number, max repititions, etc. i have used snmp4j , code wrote succesffuly monitor other devices years. don't know different time. leaving me stumped. why "general variable binding error?" causes error? ideas debug? can reproduced? if so, first action should using wireshark or microsoft network monitor capture network packets. my guess agent gives generr response, not surprising, http://www.ietf.org/rfc/rfc1157.txt
Read more

windows - Python Service Installation - "Could not find PythonClass entry" -

-
i working on building python service. inducing error, not sure inducing it. ps c:\...> python .\file.py debug debugging service myservice - press ctrl+c stop. error 0xc00000f4 - not find service's pythonclass entry in registry error 1814 - specified resource name cannot found in image file. error 0xc0000080 - not locate module name in python class string (ie, no '.') this error coming pythonservicemessages.mc in pythonwin32. it turns out error result caused exception being thrown , python script dying off.
Read more

Determine if a XmlNode is empty or null in C#? -

-
the following code takes xmlnode data type , populates dataset object xmlnode content. write dataset's content file. public void populatedataset(xmlnode node) { xmlnodereader reader = new xmlnodereader(node); dataset ds = new dataset(); ds.readxml(reader); system.guid guid = system.guid.newguid(); string name = string.format("{0}{1}_{2}.xml", utility.xmloutputpath, utility.xmloutputfilename, guid.tostring()); //need write "node empty" file if xmlnode object empty of null ds.writexml(name, xmlwritemode.ignoreschema); } the problem encountered 1 scenario not write content file. how determine if xmlnode object null or empty? you can check if node parameter null or has innertext or innerxml properties null or empty, when enter method before creating xmlnodereader .
Read more